【題目敘述】https://codeforces.com/contest/1245/problem/D
【解題想法】包裝過的最小生成樹 (MST) (hard)
#include <iostream>
#include <cstring>
#include <vector>
#include <algorithm>
#include <cstdlib>
using namespace std;
int a[2005][3], n, p[2005], todo, l, x, y;
long long c, ans;
bool flag;
struct e{
int x, y;
long long cost;
};
bool cmp(e x, e y){
return x.cost < y.cost;
}
int fi(int a){
if (p[a] == a) return a;
else{
p[a] = fi(p[a]);
return p[a];
}
}
vector <e> v;
vector <int> towers;
vector <pair<int, int> > edge;
int main() {
while (cin >> n){
v.clear();
towers.clear();
todo = n;
p[0] = 0;
for (int i = 1; i <= n; i++){
p[i] = i;
cin >> a[i][1] >> a[i][2];
}
for (int i = 1; i <= n; i++){
cin >> c;
v.push_back({0, i, c});
}
for (int i = 1; i <= n; i++){
cin >> a[i][0];
}
for (int i = 1; i < n; i++){
for (int j = i+1; j <= n; j++){
c = (a[i][0]+a[j][0]);
c *= (abs(a[i][1]-a[j][1])+abs(a[i][2]-a[j][2]));
v.push_back({i, j, c});
}
}
sort(v.begin(), v.end(), cmp);
for (e tmp:v){
x = fi(tmp.x);
y = fi(tmp.y);
if (x == y) continue;
if (tmp.x == 0) towers.push_back(tmp.y);
else edge.push_back({tmp.x, tmp.y});
p[y] = x;
ans += tmp.cost;
todo--;
if (todo == 0) break;
}
cout << ans << "\n";
l = towers.size();
cout << l << "\n";
sort(towers.begin(), towers.end());
for (int i = 0; i < l; i++){
if (i != 0) cout << " ";
cout << towers[i];
}
cout << "\n";
l = edge.size();
cout << l << "\n";
for (int i = 0; i < l; i++){
cout << edge[i].first << " " << edge[i].second << "\n";
}
}
}