【題解】TIOJ 1195 . 車牌義賣問題

#include <iostream>
using namespace std;

int n, ans;
string s;

int main() {
    cin >> n;
    for (int i = 0; i < n; i++){
        cin >> s;
        if (s[3] == s[4]){
            if (s[2] == s[3] && s[4] == s[5]) ans += 2000;
            else if (s[2] == s[3] || s[4] == s[5]) ans += 1000;
        }
        else if (s[2] == s[3] && s[4] == s[5]) ans += 1500;
    }
    cout << ans << "\n";
}