【題目敘述】https://zerojudge.tw/ShowProblem?problemid=a451
【解題想法】矩陣快速冪

#include <iostream>
#include <cstring>
using namespace std;
int n, m, mod;
struct mat {
long long a[2][2];
mat() {
memset(a, 0, sizeof(a));
}
mat operator * (const mat &b) const {
mat ret;
for( int i = 0; i < 2; ++i )
for( int j = 0; j < 2; ++j )
for( int k = 0; k < 2; ++k )
ret.a[i][j] = ( ret.a[i][j] + a[i][k] * b.a[k][j] ) % mod;
return ret;
}
};
mat f;
void solve(){
mod = 1<<m;
mat ret;
ret.a[0][0] = 0;
ret.a[1][0] = 1;
f.a[0][0] = 0;
f.a[0][1] = 1;
f.a[1][0] = 1;
f.a[1][1] = 1;
while (n){
if (n & 1){
ret = f * ret;
}
f = f * f;
n >>= 1;
}
cout << ret.a[0][0] << "\n";
}
int main() {
while (cin >> n >> m) solve();
}