【題解】ZeroJudge a695: [NOIP 2012 普及組] 1.分解质因数

#include <iostream>
using namespace std;

int main() {
    int n, i;
    while (cin >> n){
        for (i = 2; i * i <= n; i++){
            if (n % i == 0) break;
        }
        cout << n / i << "\n";
    }
    return 0;
}

n = int(input())
for i in range(2, int(n**0.5)+1):
    if n % i == 0:
        break
print(n // i)