【題解】ZeroJudge b561: 1.披薩大小

#include <iostream>
#include <iomanip>
using namespace std;

int n;

int main() {
    while (cin >> n){
        int a = 0, b = 0;
        for (int i = 0, x; i < n; i++){
            cin >> x;
            a += x*x;
        }
        cin >> n;
        for (int i = 0, x; i < n; i++){
            cin >> x;
            b += x*x;
        }
        cout << fixed << setprecision(2) << double(abs(a-b))/4*3.14159 << "\n";
    }
}

PI = 3.14159

while True:
    try:
        tmp = list(map(int, input().split()))
        sum1  = 0
        for i in range(tmp[0]):
            sum1 += PI * tmp[i+1] * tmp[i+1] / 4

        tmp = list(map(int, input().split()))
        sum2  = 0
        for i in range(tmp[0]):
            sum2 += PI * tmp[i+1] * tmp[i+1] / 4
        print(f"{round(abs(sum1 - sum2),2):.2f}")
    except:
        break