【題目敘述】https://zerojudge.tw/ShowProblem?problemid=e531 (考生答對率: 24.73%)
【解題想法】
- map <char, vector<int> > mp; 紀錄每個音調需按鍵的手指。
- 如果某一按鍵在下一音符時不會用到，那麼就會放開，否則就是維持按著的情況。（持續按著，不加計按鍵次數。）
- ⚠️注意：歌曲可能是空的。讀入測資使用 getline(cin, s);
#include <iostream>
#include <map>
#include <vector>
using namespace std;
int main() {
map <char, vector<int> > mp;
mp['c'] = {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1};
mp['d'] = {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0};
mp['e'] = {0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0};
mp['f'] = {0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0};
mp['g'] = {0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0};
mp['a'] = {0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0};
mp['b'] = {0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0};
mp['C'] = {0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0};
mp['D'] = {0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 0};
mp['E'] = {0, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0};
mp['F'] = {0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0};
mp['G'] = {0, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0};
mp['A'] = {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0};
mp['B'] = {0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0};
int t;
string s;
cin >> t;
getline(cin, s); //clear buffer
while (t--){
getline(cin, s);
int cnt[11] = {0};
int a[11] = {0}; //status
for (int i = 0; i < s.size(); i++){
for (int j = 1; j <= 10; j++){
if (mp[s[i]][j]){
if (a[j]) continue;
else {
a[j] = 1;
cnt[j]++;
}
} else {
a[j] = 0;
}
}
}
for (int i = 1; i <= 10; i++){
cout << cnt[i] << " ";
}
cout << "\n";
}
return 0;
}