【題目敘述】https://zerojudge.tw/ShowProblem?problemid=e658
【解題想法】二分搜
#include <iostream>
using namespace std;
int main() {
int T;
cin >> T;
while (T--) {
long long n;
cin >> n;
long long l = 0, r = 2e9, m;
while (l <= r) {
m = (l + r) / 2;
long long x1 = m * (m + 1) / 2;
long long x2 = (m + 1) * (m + 2) / 2;
if (n >= x1 && n < x2) {
cout << m << "\n";
break;
} else if (n < x1) {
r = m - 1;
} else {
l = m + 1;
}
}
}
return 0;
}