【題解】ZeroJudge e797: p4. 數位邏輯運算

#include <iostream>
#include <algorithm>
#include <cstring>
using namespace std;

int a[11][11];
int AND[11], OR[11], XOR[11];

int main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    int N, T;
    cin >> N >> T;
    for (int i=0; i<N; i++){
        for (int j=0; j<T; j++){
            cin >> a[i][j];
        }
    }
    for (int i=0; i<T; i++){
        int ones = 0;
        for (int j=0; j<N; j++){
            ones += (a[j][i] == 1);
        }
        if (ones == N) AND[i] = 1;
        if (ones > 0) OR[i] = 1;
        if (ones % 2) XOR[i] = 1;
    }
    cout << "AND:";
    for (int i=0; i<T; i++) {
        cout << ' ' << AND[i];
    }
    cout << '\n';

    cout << " OR:";
    for (int i=0; i<T; i++) {
        cout << ' ' << OR[i];
    }
    cout << '\n';

    cout << "XOR:";
    for (int i=0; i<T; i++) {
        cout << ' ' << XOR[i];
    }
    cout << '\n';
    return 0;
}

N, T = map(int, input().split())
a = []
for i in range(N):
    a.append(list(map(int, input().split())))

AND = []
OR = []
XOR = []
for i in range(T):
    ones = 0
    for j in range(N):
        ones += (a[j][i] == 1)
    if ones == N:
        AND.append(1)
    else:
        AND.append(0)
    if ones >= 1:
        OR.append(1)
    else:
        OR.append(0)
    if ones % 2:
        XOR.append(1)
    else:
        XOR.append(0)

print("AND:", end='')
for i in range(T):
    print(" ", AND[i], sep='', end='')
print()

print(" OR:", end='')
for i in range(T):
    print(" ", OR[i], sep='', end='')
print()

print("XOR:", end='')
for i in range(T):
    print(" ", XOR[i], sep='', end='')
print()